Closed allynt closed 7 years ago
Enumeration "other" choice doesn't consistently expose the other input box.
This was b/c the check if "_OTHER" was in the array was written as $.inArray(arg, value) > 0 as opposed to $.inArray(arg, value) >= 0.
$.inArray(arg, value) > 0
$.inArray(arg, value) >= 0
Enumeration "other" choice doesn't consistently expose the other input box.