Closed salliewalecka closed 5 years ago
Not sure if this is too nit picky, but for the proof statement, maybe it should mention and $\mu_k$ is an eigenvalue of T_{k-1} just so it is more self contained.
and $\mu_k$ is an eigenvalue of T_{k-1}
No you are right. This needs to be stated. I rewrote this problem slightly to make it more general.
Not sure if this is too nit picky, but for the proof statement, maybe it should mention
and $\mu_k$ is an eigenvalue of T_{k-1}
just so it is more self contained.