Closed alexchen4ai closed 3 years ago
Krylov subspace is expressed as K(matrix, #iteration, vector), but all elsewhere are expressed K(matrix, vector, #iteration). Just a small suggestion that they could follow the same convention.
Good catch!!
Krylov subspace is expressed as K(matrix, #iteration, vector), but all elsewhere are expressed K(matrix, vector, #iteration). Just a small suggestion that they could follow the same convention.