Closed MikeMillerGIS closed 7 years ago
In case you where interested, found a great way to parse a string.
instead of .rfind("."), use rpartition(".")[-1]
This always gets just the FC name regardless of the string return os.path.basename(os.path.normpath(dataset)).rpartition('.')[-1]
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ChrisBuscaglia
commented
7 years ago ChrisBuscaglia
commented
7 years ago
In case you where interested, found a great way to parse a string.
instead of .rfind("."), use rpartition(".")[-1]
This always gets just the FC name regardless of the string return os.path.basename(os.path.normpath(dataset)).rpartition('.')[-1]