pmatos
commented
6 days ago Probably not a big win in practice. A single 80-bit store required 2 stores (64 + 16). Now, we require three instructions: mov + whilelt + st1b. You need three 80-bit stores in a block to get to a draw instruction-wise. The next step would be not to assemble the predicate register every time, which I will do next, but we'll still require in practice at least three stores per block for it to "win" instruction-wise.
Fixes #4126