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Fierozen / owasp-esapi-java

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I am getting validation exception while validating a paramter coming from http request #256

Open GoogleCodeExporter opened 9 years ago

GoogleCodeExporter commented 9 years ago 
What steps will reproduce the problem?
1.
2.
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What is the expected output? What do you see instead?
i need to see the vaidated Input

What version of the product are you using? On what operating system?
I am using ESAPI 1.4.jar

Does this issue affect only a specified browser or set of browsers?

Please provide any additional information below.
I am getting the below exception...please help me out on this.
Dec 19, 2011 12:57:24 PM AppNameNotSpecified IntrusionDetector
WARNING: SECURITY-FAILURE Anonymous@unknown:unknown -- Invalid input: 
context=Synchrozier Token, type=HTTPParameterName( HTTPParameterName), 
input=ea15e562efb5e786dbf5cd55443a80e1
    ValidationException @ org.owasp.esapi.reference.DefaultValidator.getValidInput(DefaultValidator.java:140)

Original issue reported on code.google.com by thiru...@gmail.com on 19 Dec 2011 at 7:40