rdb$field_sub_type for numeric computed column [DNET423]

[firebird-automations]

Submitted by: @cincuranet

Directly from my thread "Wrong rdb$field_sub_type for numeric computed column" in firebird-devel:

have a table: recreate table test ( base numeric(15,4), test1 computed by (base+base), test2 computed by (cast(base+base as numeric(15,4))), foo bigint, bar numeric(15,4) );

If I run the query: select rf.RDB$FIELD_NAME, f.RDB$FIELD_SCALE, f.RDB$FIELD_TYPE, f.RDB$FIELD_SUB_TYPE from RDB$RELATION_FIELDS rf inner join RDB$FIELDS f on (rf.RDB$FIELD_SOURCE = f.RDB$FIELD_NAME) where rf.RDB$RELATION_NAME = 'TEST' it reports: BASE -4 16 1 TEST1 -4 16 0 TEST2 -4 16 1 FOO 0 16 0 BAR -4 16 1

Why is rdb$field_sub_type for test1 column "0"? Then it looks like bigint. Checking the rdb$field_scale could be a solution, but is it then numeric or decimal?

I'm happy with conclusion that if field_scale is < 0 and no particular sub_type, imply i.e. numeric. Probably somebody from core devs should tell us.

That is what is done in Jaybird right now.

See getDataType(...) and getDataTypeName(...) in http://firebird.cvs.sourceforge.net/viewvc/firebird/client-java/src/main/org/firebirdsql/jdbc/AbstractDatabaseMetaData.java?view=markup

Commits: FirebirdSQL/NETProvider@35c3ae1f602cb17ea16f60d9337a34f7b742ce27

[firebird-automations]

Modified by: @cincuranet

Component: Entity Framework support \[ 10110 \] Component: Provider \[ 10041 \] =\>

[firebird-automations]

Modified by: @cincuranet

status: Open \[ 1 \] =\> Resolved \[ 5 \] resolution: Fixed \[ 1 \] Fix Version: 2\.7\-next \[ 10462 \]