regex.search("^(a){0,0}", "abc").group(0,1) returns ('a', 'a') instead of ('', None)

Forever-Young / mrab-regex-hg

Automatically exported from code.google.com/p/mrab-regex-hg

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What steps will reproduce the problem?
>>> import regex
>>> print(regex.search("^(a){0,0}", "abc").group(0,1))
('a', 'a')
>>>

What is the expected output? What do you see instead?
>>> import regex
>>> print(regex.search("^(a){0,0}", "abc").group(0,1))
('', None)
>>>

What version of the product are you using? On what operating system?
Windows XP Home SP3 (32-bit version)
Python 3.2.2 (default, Sep  4 2011, 09:51:08) [MSC v.1500 32 bit (Intel)] on win
32
regex 0.1.20120112

Please provide any additional information below.

Original issue reported on code.google.com by msm...@gmail.com on 14 Jan 2012 at 4:06

Forever-Young / mrab-regex-hg

regex.search("^(a){0,0}", "abc").group(0,1) returns ('a', 'a') instead of ('', None) #37