regex.search("(a(?(1)\\1)){4}", "a"*10, flags=regex.V1).group(0,1) returns ('aaaaa', 'a') instead of ('aaaaaaaaaa', 'aaaa')

What steps will reproduce the problem?
>>> import regex
>>> print(regex.search("(a(?(1)\\1)){4}", "a"*10, flags=regex.V1).group(0,1))
('aaaaa', 'a')
>>>

What is the expected output? What do you see instead?
>>> import regex
>>> print(regex.search("(a(?(1)\\1)){4}", "a"*10, flags=regex.V1).group(0,1))
('aaaaaaaaaa', 'aaaa')
>>>

What version of the product are you using? On what operating system?
Windows XP Home SP3 (32-bit version)
Python 3.2.2 (default, Sep  4 2011, 09:51:08) [MSC v.1500 32 bit (Intel)] on win
32
regex 0.1.20120123

Please provide any additional information below.
The following works fine:
>>> print(regex.search("(a(?(1)\\1)){1}", "a"*10, flags=regex.V1).group(0,1))
('a', 'a')
>>> print(regex.search("(a(?(1)\\1)){2}", "a"*10, flags=regex.V1).group(0,1))
('aaa', 'aa')
>>>

Original issue reported on code.google.com by msm...@gmail.com on 25 Jan 2012 at 1:01

Forever-Young / mrab-regex-hg

regex.search("(a(?(1)\\1)){4}", "a"*10, flags=regex.V1).group(0,1) returns ('aaaaa', 'a') instead of ('aaaaaaaaaa', 'aaaa') #48