Closed FrankKair closed 6 years ago
The smallest divisible number by a range from 1 to 20, is the lcm of the accumulated number.
lcm
(1..19).reduce { |acc, x| acc.lcm(x) }
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How the solution works
The smallest divisible number by a range from 1 to 20, is the
lcmof the accumulated number.(1..19).reduce { |acc, x| acc.lcm(x) }Performance
Go