Closed warang580 closed 8 years ago
If a falsy value is returned by the transform function, it will return the original value. (needs to be documented, but I'm not sure of the behavior of this part, yet.)
This might not be good as it makes transforms on booleans impossible, but perhaps that's okay.
If you
parseInt("Belcher")
, you will getNaN
, not"Belcher"
.