Closed GoogleCodeExporter closed 9 years ago
The variable associated with the parser in your case exml needs to be in a
global
context.
Original comment by lanceala...@gmail.com
on 18 Jan 2010 at 8:44
Can you provide a bit more detail? What's the solution?
Original comment by d...@douglaskarr.com
on 18 Jan 2010 at 8:46
Read about scope,
http://econym.org.uk/gmap/scope.htm
when somebody says make your variable global.
outside of your function.
var exml;
inside your function
exml = new GeoXml(etc...);
Original comment by lanceala...@gmail.com
on 18 Jan 2010 at 9:47
Original issue reported on code.google.com by
d...@douglaskarr.com
on 18 Jan 2010 at 8:36