Open silardg opened 4 years ago
IIUC, the "Serial" object refers to USB virtual (CDC) serial. The hardware UARTs are mapped to Serial1
and upwards by default. Maybe you should be using Serial1
instead?
Arduino sets this up kind of oddly in general.
On a real AVR based platform (other the ones with builtin USB) "Serial" refers to both, D0/D1 and the attached USB. This is what the code for B-L072Z-LWAN1 does.
With other non-NUCLEO platforms, USB maps to "Serial", and hence D0/D1 map to "Serial1".
Ah, I didn't realize that this board does not have native USB, I see, so then my suggestion does not apply and something else is going on.
How to use Serial2 on PA2 and PA3? i tried the HardwareSerial command . got error in compiler!
https://github.com/GrumpyOldPizza/ArduinoCore-stm32l0/blob/c11545bc9751a05f1b1e0a6b1f8130bcb0fb26dc/variants/B-L072Z-LRWAN1/variant.h#L105
I'm trying to get Serial to work on PA2, TX. By the code above, PIN_SERIAL_TX is arduino pin 1, and Serial is setup by extern const stm32l0_uart_params_t g_SerialParams.
I tried the same pin with PlatformIO and it worked with Serial, pin 1 TX (PA2). The code I'm using is simple Serial.begin(9600); and Serial.println("test");
I'm using B-L072Z-LRWAN1.
What am I doing wrong?!