Closed ruisebastiao closed 6 years ago
@ruisebastiao thank you for the PR, but can you provide more info about? or create a sample, because in my all tests the state that you need like display
property It's been provided by (output)
Observable normally.
Closing because the author did not answer the question.
Clicking on the action buttons the menu button keep the active state, calling detectChanges() in every state change solved my problem