Closed GoogleCodeExporter closed 8 years ago
The one you described is exactly the expected behavior. It is a variant of the
first of the 2 lambdaj known limitations explained here:
http://code.google.com/p/lambdaj/wiki/KnownLimitations
In more details, in your example, due to the lack of generics reification,
lambdaj cannot recognize at runtime that the method getId() returns a Long
instead of an Object. So it generates the proxy of an Object and when it tries
to cast it to a Long it throws the ClassCastException you are experiencing.
I am sorry, but for what I know there is no solution for this issue. Let me
know if my explanation is clear or if you have any question (and possibly any
suggestion).
Thanks a lot
Mario
Original comment by mario.fu...@gmail.com
on 12 Jul 2010 at 7:49
I understand...
However, I was able to find correct type information for creating a proxy..
I did modify the invoke method on ProxyArgument with the following:
public Object invoke(Object proxy, Method method, Object[] args) throws Throwable {
Class<?> returnType = method.getReturnType();
if (method.getName().equals("hashCode")) return invocationSequence.hashCode();
if (method.getName().equals("equals")) return invocationSequence.equals(args[0]);
Type type = method.getGenericReturnType();
if(type instanceof TypeVariable) {
TypeVariable typeVar = (TypeVariable) type;
String name = typeVar.getName(); //something like T, K, etc
//now let's find the type for T
GenericDeclaration genericDeclaration = typeVar.getGenericDeclaration();
TypeVariable<?>[] typeVariables = genericDeclaration.getTypeParameters();
int index = -1;
for (int i = 0, typeVariablesLength = typeVariables.length; i < typeVariablesLength; i++) {
TypeVariable<?> typeVariable = typeVariables[i];
if (typeVariable.getName().equals(name)) {
//found it, tye type located at index i
index = i;
break;
}
}
//actual type argument is thus also at this index
Type genericSuperclass = proxiedClass.getGenericSuperclass();
if (index > -1 && genericSuperclass instanceof ParameterizedType) {
ParameterizedType parameterizedType = (ParameterizedType) genericSuperclass;
Type[] actualTypeArguments = parameterizedType.getActualTypeArguments();
returnType = (Class<?>) actualTypeArguments[index];
}
}
// Adds this invocation to the current invocation sequence and creates a new proxy propagating the invocation sequence
return createArgument(returnType, new InvocationSequence(invocationSequence.get(), new Invocation(proxiedClass, method, args)));
}
Original comment by pieter.d...@gmail.com
on 13 Jul 2010 at 9:15
Thanks a lot Pieter!
I will try your code immediately. It could be a great improvement.
Could you also post the test case you used to try it?
Thanks again
Mario
Original comment by mario.fu...@gmail.com
on 13 Jul 2010 at 12:33
Here it is.
Note that I think the fix will fail in the case where the superclass of the
proxied class does not define the generic types but one of his superclasses (I
should loop through all superclasses, but I don't have time for the moment...)
Pieter
Original comment by pieter.d...@gmail.com
on 13 Jul 2010 at 1:16
Attachments:
Hi Pieter,
I played with your solution and I must admit that it is very smart, but in the
end I decided to take it off lambdaj because I am afraid it could lead to a non
completely deterministic and transparent behavior. Let me quickly justify my
decision.
As you wrote your solution doesn't work when the generic is in a
super-superclass, but this could be easily fixable. Unfortunately there could
be other corner cases where to find the right class to proxy couldn't be that
easy. For example the generic could be in an implemented interface instead of
in an extended class. Probably the worst case is when you have a
MyInterface1<T> and a MyInterface2<T> and your class is defined as it follows:
class MyClass implements MyInterface1<String>, MyInterface2<Long>
In this case it wouldn't be so easy to decide if a given T is a Long or a
String. Moreover the generic could be only in the signature of the invoked
method and not defined at Class-level declaration (as it actually happens with
many lambdaj methods).
In the end it doesn't have any chance to work with something very usual like an
ArrayList<String> while it works with a class declared as:
MyList extends ArrayList<String>
and to be honest this behavior could be hardly understandable.
I hope you can agree or at least understand my decision. Anyway thanks a lot
for your collaboration.
Best Regards,
Mario
Original comment by mario.fu...@gmail.com
on 14 Jul 2010 at 3:36
I completely agree.
Thanks for your time to look at it.
Original comment by pieter.d...@gmail.com
on 15 Jul 2010 at 8:00
Original issue reported on code.google.com by
pieter.d...@gmail.com
on 12 Jul 2010 at 1:37