Quadratic result should communicate that x is being solved for

[HenryWilder]

The quadratic placeholder currently shows $$\large Ax^2+Bx+C=?$$ This is misleading. The right side of the equals sign should be 0. The functionality is to show what $x$ is.

It should instead show: $$\large Ax^2+Bx+C=0; x=?$$

Or, if possible: $$\large \frac{-B\pm\sqrt{B^2-4AC}}{2A}=?$$

[HenryWilder]

Changing it to this in db7dc84 for now.

$$\large Ax^2+Bx+C=0; x=?$$

Look into making it this when #11 is figured out.

$$\large \frac{-B\pm\sqrt{B^2-4AC}}{2A}=?$$

[HenryWilder]

Current status: