HenryWilder
commented
11 months ago This appears to be a non-trivial issue as most sources state that the only way to find the exact value of a log result by using logs. $$\log_5{7} = \frac{\log{7}}{\log{5}}$$ This is likely not particularly helpful.
One possibility could be to show both the exact value with logs, an approximate fraction, and a decimal. $$\log_5{7} = \frac{\log{7}}{\log{5}} \approx 1\frac{1}{5} \approx 1.2090619551221675$$ While making exact fractional answers cleaner. $$\log_4{8} = 1\frac{1}{2}$$
The binary
logoperation returns its non-integral results in the form of an irrational decimal.I'm not sure how to display an irrational number better, but the program should always produce exact values.