How to convert a loop to a Job-array in LSF cluster

[loukesio]

I might be in the wrong place to ask, so excuse my ignorance. If this is the case, I'll delete asap my comment. We recently got a cluster with an LSF operation system, and I am struggling with the following issue.

I have 100 files, and I want to parallelise my submission to save time instead of running jobs one by one. How can I change this script to a Job-array in LSF using bsub submission system?

#BSUB -J ExampleJob1         #Set the job name to "ExampleJob1"
#BSUB -L /bin/bash           #Uses the bash login shell to initialize the job's execution environment.
#BSUB -W 2:00                #Set the wall clock limit to 2hr
#BSUB -n 1                   #Request 1 core
#BSUB -R "span[ptile=1]"     #Request 1 core per node.
#BSUB -R "rusage[mem=5000]"  #Request 5000MB per process (CPU) for the job
#BSUB -M 5000                #Set the per process enforceable memory limit to 5000MB.
#BSUB -o Example1Out.%J      #Send stdout and stderr to "Example1Out.[jobID]"

path=./home/

for each in *.bam 
do 
samtools coverage ${each} -o ${each}_coverage.txt
done

Thank you for your time; any help is appreciated. I am a starter at LSF and quite confused.

[AugieMena3]

Closing this since this concerns core LSF capabilities. The information may potentially be found in the documentation here: https://www.ibm.com/docs/en/spectrum-lsf/10.1.0?topic=components-lsf-documentation