Open mtfishman opened 1 year ago
For example:
julia> DataGraph(grid((4,)), ["X", "Y", "Z", "W"]) ERROR: MethodError: no method matching DataGraph(::SimpleGraph{Int64}, ::Vector{String}) Closest candidates are: DataGraph(::AbstractGraph) at ~/.julia/dev/DataGraphs/src/datagraph.jl:117 DataGraph(::AbstractGraph, ::Dictionary) at ~/.julia/dev/DataGraphs/src/datagraph.jl:117 DataGraph(::AbstractGraph, ::Dictionary, ::Dictionary) at ~/.julia/dev/DataGraphs/src/datagraph.jl:117 ... Stacktrace: [1] top-level scope @ REPL[29]:1
This could automatically convert to a Dictionary, i.e. get converted internally to:
Dictionary
julia> DataGraph(grid((4,)), Dictionary(["X", "Y", "Z", "W"])) DataGraph{Int64, String, Any, SimpleGraph{Int64}, Graphs.SimpleGraphs.SimpleEdge{Int64}} with 4 vertices: Base.OneTo(4) and 3 edge(s): Edge 1 => 2 Edge 2 => 3 Edge 3 => 4 with vertex data: 4-element Dictionary{Int64, String} 1 │ "X" 2 │ "Y" 3 │ "Z" 4 │ "W" and edge data: 0-element Dictionary{Graphs.SimpleGraphs.SimpleEdge{Int64}, Any}
This would only make sense for vertices with linear indexing.
For example:
This could automatically convert to a
Dictionary
, i.e. get converted internally to:This would only make sense for vertices with linear indexing.