Closed meireles closed 6 years ago
Hi Jose,
Yes the data are drawn by default from the stationary distribution. The stationary distribution of the process you're simulating have a very high variance (about 2e07). A simple way to check it is to use the 'stationary' function:
?stationary class(params)<-c("mvmorph","mvmorph.ou") stationary(params)
You can sample from the process with a fixed root instead:
params = list(ntraits = 2, sigma = diag(sigma_sq), alpha = alpha, theta = trait_mu, vcv = "fixedRoot")
data_ou = mvMORPH::mvSIM(tree = tree, param = params, model = "OU1", nsim = 10)
Regards,
Julien
De : Jose Eduardo Meireles notifications@github.com Envoyé : mardi 13 novembre 2018 05:10 À : JClavel/mvMORPH Cc : Subscribed Objet : [JClavel/mvMORPH] Simulated data is counterintuitive when alpha is really small (#3)
The variance in traits simulated under an OU model with a small alpha seems to be really large (see example below). Is mvSIM drawing data from the stationary distribution for the OU model (I think that would explain it)? Anyhow, I wonder what the best way to simulate a dataset that mixes BM and OU traits without running each model separately. Thanks!
library("mvMORPH") library("phytools")
tree = phytools::pbtree(n = 50, scale = 1) trait_mu = c(10, 0.2) sigma = c(0.2, 0.0001) sigma_sq = sigma * sigma
alpha = matrix(data = diag(c(1e-9, 0.1)), nrow = 2, ncol = 2)
params = list(ntraits = 2, sigma = diag(sigma_sq), alpha = alpha, theta = trait_mu)
data_ou = mvMORPH::mvSIM(tree = tree, param = params, model = "OU1", nsim = 10)
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@JClavel somehow I had missed the "vcv" argument when reading the doc. Thanks!
The variance in traits simulated under an OU model with a small alpha seems to be really large (see example below). Is mvSIM drawing data from the stationary distribution for the OU model (I think that would explain it)? Anyhow, I wonder what the best way to simulate a dataset that mixes BM and OU traits without running each model separately. Thanks!