Closed aakashpothepalli closed 2 years ago
Sorry for the late reply, you unfortunately cannot avoid warnings that are generated, it is a fault from my side and tbh I do not have a quick fix for it when the code gets executed on one of my laptops. Sorry for the inconvenience.
The compiler throws warnings in the output even for small things... For example, here I have not used a variable even though I have declared it.. Now the compiler throws me this warning
I have to parse and sanitise the output before showing it on the website. Is there any way for me to disable the warnings?
Btw, thanks for designing and providing the API for free :)