Open Jashcraf opened 2 years ago
For a telescope primary these surfaces are co-located, and should therefore have the same orthogonal transformation. This is to say, if we just compute the Jones matrix without the orthogonal transformation, it is the jones pupil of the system.
Keep in mind that I think there's supposed to be a pi offset for the p-component here.
Revised Jones Pupils
The center of the amplitude corresponds to a reflectance equal to what refractiveindex.info shows, and the phase is quadratic but goes in the opposite direction - so I think the Jones matrix calculation is basically tested.
From PL&OS pg 438 equation 11.15
The jones pupil is an orthogonal transformation of the P matrix using the matrices for the entrance and exit pupils. This is where spk, dipole, and double pole coordinates come in. If you have real pupils then using the spk coordinates should be sufficient.
J = inv(O_xp) P O_ep