python数据处理：列表拼接为字典

[slsongge]

问题

如下图，我有一个列表，想转换为第三行的字典的样式：

数据

['fpd_0','fpd_5','fpd_10','ever4_pd10']
# [y+'_mean' for y in ['fpd_0','fpd_5','fpd_10','ever4_pd10']]

{'fpd_0_mean':'{:.2%}', 'fpd_5_mean':'{:.2%}', 'fpd_10_mean':'{:.2%}', 'ever4_pd10_mean':'{:.2%}'}

[slsongge]

我刚才找到了一个解决方法，如下

a = [y+'_mean' for y in ['fpd_0','fpd_5','fpd_10','ever4_pd10']]
dict((k, '{:.2%}') for k in a)

[JiaxiangBU]

@slsongge

some_list = ['fpd_0','fpd_5','fpd_10','ever4_pd10']
some_dict = {'fpd_0_mean':'{:.2%}', 'fpd_5_mean':'{:.2%}', 'fpd_10_mean':'{:.2%}', 'ever4_pd10_mean':'{:.2%}'}

output_list = {i+'_mean':'{:.2%}' for i in some_list}

output_list == some_dict

True

# use pandas
import pandas as pd
output_list = pd.Series(['{:.2%}' for i in some_list], index = [i+'_mean' for i in some_list]).to_dict()
output_list == some_dict

True