namespace breaks macros?

[ccoenen]

Describe the bug When inside a namespace, I can't use the debugI, debugV ... shorthands.

Code Example

This prints out the same thing, once via tha long form and once with the debugI macro.

namespace Example {
    void test(const char * prefix) {
        #ifndef DEBUG_DISABLED
        if (Debug.isActive(Debug.INFO)) {
            Debug.printf(prefix, "hi");
        }
        #endif
        debugI(prefix, "hi");
    }
};

Now call Example::testWorks("this says %s");.

Expected behavior Both ways of printing a debug line should work.

Current behaviour

Here's the compiler output:

some-file: In function 'void Example::test(const char*)':
some-file:29:10: error: expected ')' before 'prefix'
   debugI(prefix, "hi");
          ^

src/RemoteDebug.h:146:84: note: in definition of macro 'rdebugI'
   #define rdebugI(fmt, ...) if (Debug.isActive(Debug.INFO))   Debug.printf("(%s) " fmt, __func__, ##__VA_ARGS__)
                                                                                    ^

src/RemoteDebug.h:195:26: note: in expansion of macro 'rdebugIln'
 #define debugI(fmt, ...) rdebugIln(fmt, ##__VA_ARGS__)
                          ^

some-file:29:3: note: in expansion of macro 'debugI'
   debugI(prefix, "hi");
   ^

Arduino Information:

• OS: Windows
• IDE: Arduino IDE
• IDE Version: 1.8.9
• Board: ESP8266

[JoaoLopesF]

Hi, In your code I saw that if.. Debug.printf appears compile, try use this instead debugI macro Regards

[ccoenen]

Yes. the long form does work. It is what i'm using in the meantime. Is there any possibility to get the shorthands working? I am not too familiar with the way macros are expanded, so I'm not sure if this is possible at all.