顺时针打印矩阵

[Jogiter]

顺时针打印矩阵

{
/**
[
    [ 1,  2,  3,  4],
    [ 5,  6,  7,  8],
    [ 9, 10, 11, 12],
    [13, 14, 15, 16]
]
矩阵顺时针打印结果为：1, 2, 3, 4, 8, 12, 16, 15, 14, 13, 9, 5, 6, 7, 11, 10
while(x > 2, y > 2)
  (x, y) y++;
  (x, y) x++;
  (x, y) y--;
  (x, y) x--;
*/ 
let matrix = [
    [1,2,3,4],
    [5,6,7,8],
    [9,10,11,12],
    [13,14,15,16]
]

function getRound(matrix, res = []) {
    let cols = matrix[0].length
    let rows = matrix.length
    let _matrix = [].concat(matrix)
    let _first = matrix[0]
    let _last = matrix[rows - 1].reverse()
    let _ends = []
    let _starts = []

    if (cols > 2 && rows > 2) {
        _matrix.splice(rows - 1, 1)
        _matrix.splice(0, 1)

        for (let y = 0; y < _matrix.length; y++) {
            _ends.push(_matrix[y][_matrix[y].length - 1])
            _starts.push(_matrix[y][0])
            _matrix[y].splice(_matrix[y].length - 1, 1)
            _matrix[y].splice(0, 1)
        }    
        res = [].concat(_first, _ends, _last, _starts.reverse())
        return getRound(_matrix, res)
    } else {
        return [].concat(res, _first, _last)
    }   
}

let output = getRound(matrix, [])
console.log(output)
// [1, 2, 3, 4, 8, 12, 16, 15, 14, 13, 9, 5, 6, 7, 11, 10]
}