Closed BatyLeo closed 1 year ago
In this page of the documentation, $f$ if defined as the $\max$, but should be an $\arg\max$, because:
maximizer
InferOpt
In this page of the documentation, $f$ if defined as the $\max$, but should be an $\arg\max$, because:
maximizer
argument ofInferOpt
layers should return the $\arg\max$.