Open zot opened 1 month ago
Out of curiosity: What should `a $(`b`)`
produce if not `a b`
? And then why would one try to enter it in the former form when the latter is simpler?
BTW one can already do ```a $(`b`)```
(which is the same as a b
)
Just reporting a parser bug here. That expression should not produce an error.
This occurs in (at least) 1.6, 1.10, and 1.11. It looks like
$
expressions inside grave quotes cannot contain grave quotes. Or at least there's a problem with these cases (which all produce different error messages):