[pythoncall] jl.Pair generates tuple instead of Julia pair

[hongyehu]

Affects: JuliaCall

Describe the bug In python, with from juliacall import Main as jl jl.Pair(1,2) it will generate a tuple instead of julia pair like 1=>2.

system info Please provide detailed information about your system:

• Mac Ventura 13.2.1
• The version of Julia 1.8.5, Python 3.9.7, JuliaCall 0.9.12

[cjdoris]

This isn't a bug, it's a feature: whenever you call a Julia function from Python, the inputs and outputs are converted according to the documented rules.

The next major version is likely to change this however, so that the outputs are not converted and are always returned as a wrapped Julia value, so the above code does what you expect.

For now, you can do jl.Pair._jl_raw()(1, 2)._jl_any().

Or pair = jl.seval("pyjl(Pair(1, 2))"); pair(1, 2).

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