Closed geoffroyleconte closed 2 years ago
It should be possible and interesting to be able to solve:
min ||r||²/2 s.t. Ax + r = b.
min ||r||²/2 s.t. Ax + r = b
This problem can be formulated as a QP.
One algorithmic improvement that you could make for LLS problems is that there is no need to regularize Ax + r = b; it is already regularized.
fixed with https://github.com/JuliaSmoothOptimizers/RipQP.jl/pull/122
It should be possible and interesting to be able to solve:
min ||r||²/2 s.t. Ax + r = b
.This problem can be formulated as a QP.