Open krishvishal opened 1 year ago
What's the problem with Poisson(0)
?
Poisson(0) makes the mass concentrated at zero, and turns into Dirac.
And also multiple textbooks define the rate parameter λ
to be positive real.
Ref:
Sure, if you want a proper (non-degenerate) Poisson distribution, you have to choose a positive parameter, but the same could be said about many other distributions, e.g. Bernoulli(p)
as p->0
. Many of those have limits (edge cases) which are still valid distribution. In numerical applications, it would be bad if the limit throws an error even though the limit is a perfectly valid distribution. For example, you may have a model where λ = exp(x)
and for very negative x
this can underflow.
The
λ
parameter of Poisson is only defined for positive reals. But here its defined forλ >= 0
.Is this intended?