Closed TheOnlyArtz closed 5 years ago
It is possible, if I understand correctly. You need of couse whole strings to do it. Is your application really speed sensitive, or are you ok with waiting for a few microseconds every message?
Den tor. 27. sep. 2018, 17:12 skrev Amit Katz notifications@github.com:
I got the next code:
import OpenTrick import WebSockets
io = OpenTrick.opentrick(WebSockets.open, "wss://gateway.discord.gg/?v=6&encoding=json")
How would I parse the bytes to JSON?
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@hustf Hey, thank you for the quick response I've managed to fix it and parse bytes to JSON, but I got another question, I'm trying to keep receiving data from the gateway and I'm trying to do
while isopen(connection)
println(WebSockets.read(connection))
end
for some reason it never prints and the connection is open (checked by doing println("aaa")
inside it.
EDIT: ERROR: LoadError: WebSockets.WebSocketClosedError("ws|client respond to OPCODE_CLOSE 1000:Normal")
this what happens when the socket closes (and so does the process)
The information is a little thin here. It's a connection, so both sides depend on what the other side is doing. If both sides read simultaneously, you are stuck for ever. So this can be hard to get right, and for many applications you need some sort of parallelism and a buffer. I would recommend using readguarded instead of reading, though.
Den tor. 27. sep. 2018, 19:58 skrev Amit Katz notifications@github.com:
@hustf https://github.com/hustf Hey, thank you for the quick response I've managed to fix it and parse bytes to JSON, but I got another question, I'm trying to keep receiving data from the gateway and I'm trying to do
while isopen(connection) println(WebSockets.read(connection))end
for some reason it never prints and the connection is open (checked by doing println("aaa") inside it.
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I got the next code: