Open mmikhasenko opened 1 month ago
The difference only appears in interference, therefore the test should be checking the interference of the reference chain with that test chain that is being permuted.
I = |A1(ref) + A3|ˆ2
I' = |A1(ref) + c * permute(A3)|ˆ2
where c
is the symmetry factor from the header. Is I
equal to I'
?
c
positive and negative are covered. See if the identity always true.There is a chance that it works :-)
I've looked at the same exercise with DPD. It's a but tricky to figure out either pi, or -pi appears for the aligned confuguration if one starts messing up with the order.
for the records, what I get is
(-1)^{j-l-s} * # from Clebsch
(-1)^{j-lambda}*(-1)^{lambda} * # from D(theta_12)
(-1)^{j1-lambda1}*(-1)^{lambda1} * # from WignerD: I did not get exactly this, because of +- pi complications
(-1)^{j2-lambda2}*(-1)^{lambda2} * # from WignerD: I guess this
If I guess right, the product gives exactly (-1)^{l+s-j1-j2}
Im working on it, but cant quite show the desired result yet. The interference does not properly match yet
The claim is
it can be checked numerically