Get the width and height of the software window

[sgx-wb]

In macbook, I want to get the width, height and position of the software window, but the returned data type, python can not be taken directly, is there any way?

[Kalmat]

Hi!

The short answer is using PyWinCtl module, like this:

import pywinctl as pwc

for win in pwc.getWindowsWithTitle("Lark"):
    print("X:", win.left, "Y:", win.top, "WIDTH:", win.width, "HEIGHT:", win.height)

The long answer is:

1. Do not rely on kCGWindowOwnerName, since it is not mandatory (see this). Even though you're interested only in "Lark" app, and it seems to fulfill this field by the moment, it is not guaranteed in the future.
2. To access a value in a dictionary by its key, you have to do like this: lark["X"] or, as you were already doing with other values, like this: lark.get("X", None)

EDIT: Sorry I linked to the wrong page (kCGWindowName instead of kCGWindowOwnerName). kCGWindowOwnerName is mandatory, but you can not use it to address a single window in case the application launches several of them.

[sgx-wb]

@Kalmat Thank you very much for your reply. This method works.

[Kalmat]

You're welcome! Just curious... which method are you eventually using?

[sgx-wb]

@Kalmat It seems straightforward to obtain the value this way. lark["X"]