Closed KathleenDollard closed 9 years ago
If a syntax tree contain a type referenced via IReferencedType, programmers really need a link to that type.
The current solution is for this narrow usage. Access to types in other SyntaxTrees of the project, or accessed via reference are not yet linked.
If a syntax tree contain a type referenced via IReferencedType, programmers really need a link to that type.
The current solution is for this narrow usage. Access to types in other SyntaxTrees of the project, or accessed via reference are not yet linked.