Open Stratos-Crimson opened 1 year ago
You can place the line as follow:
if os.path.isfile(contact_db):
with sqlite3.connect(contact_db) as db:
db.text_factory = lambda b: b.decode(errors = 'ignore') # here
contacts(db, data)
if os.path.isfile(msg_db):
with sqlite3.connect(msg_db) as db:
db.text_factory = lambda b: b.decode(errors = 'ignore') # and here
messages(db, data)
media(db, data, media_folder)
vcard(db, data)
create_html(data, output_folder)
Also, could you provide me a stack trace related to this error and the version of the exporter you are using?
Oh thanks, sorry for not providing It before.
Traceback (most recent call last):)
File "/home/user/.local/bin/wtsexporter", line 8, in <module>
sys.exit(main())
File "/home/user/.local/lib/python3.9/site-packages/Whatsapp_Chat_Exporter/__main__.py", line 240 in main
messages(db, data)
File "/home/user/.local/lib/python3.9/site-packages/Whatsapp_Chat_Exporter/extract.py", line 380 in messages
content = c.fetchone()
sqlite3.OperationalError: Could not decode to UTF-8 column 'data' with text '{placeholder}'
Oh thanks, sorry for not providing It before.
Traceback (most recent call last):) File "/home/user/.local/bin/wtsexporter", line 8, in <module> sys.exit(main()) File "/home/user/.local/lib/python3.9/site-packages/Whatsapp_Chat_Exporter/__main__.py", line 240 in main messages(db, data) File "/home/user/.local/lib/python3.9/site-packages/Whatsapp_Chat_Exporter/extract.py", line 380 in messages content = c.fetchone() sqlite3.OperationalError: Could not decode to UTF-8 column 'data' with text '{placeholder}'
No problem.
Do you know what's the language and what encoding the message is used?
I am using the latest one. When I tried to use It before your update, It was giving me that message table error but now that you have updated It, that's gone. This is literally the terminal output of the text: Keep it up����������������������������������� I think that there are some emojis in this text. Like thumbs up, y'know? That would make sense but since I don't remember this message, I can't say for sure.
I have just run a grep command on all of the messages and after seeing the messages I think that this is most likely this emoji "💪" times 4.
Adding this line didn't help. But I only added It to the extract command and since the error is specifying the data column, this could be because of that. Any thoughts?
You can place the line as follow:
if os.path.isfile(contact_db): with sqlite3.connect(contact_db) as db: db.text_factory = lambda b: b.decode(errors = 'ignore') # here contacts(db, data) if os.path.isfile(msg_db): with sqlite3.connect(msg_db) as db: db.text_factory = lambda b: b.decode(errors = 'ignore') # and here messages(db, data) media(db, data, media_folder) vcard(db, data) create_html(data, output_folder)
Also, could you provide me a stack trace related to this error and the version of the exporter you are using?
I tried to reproduce it but failed, the message shown in the HTML correctly.
You can use a SQLite browser to extract that message out and convert it into HEX. Doing so may enable me to reproduce the problem.
I have tried to search for It using sqlitebrowser in the message table and data column but I couldn't find It. Can I find out which row It's erroring out on?
Wait, I think that I have found It! I just searched for the question mark shard and found 3 messages. There is one which just has BLOB written on It. And when I opened It, It showed me the Keep It up message and a bunch of dots. It is also saying that the type of data that's currently in the cell is Binary.
I have tried to search for It using sqlitebrowser in the message table and data column but I couldn't find It. Can I find out which row It's erroring out on?
Replace
i += 1 # around line 377 of extract.py?
if i % 1000 == 0:
print(f"Gathering messages...({i}/{total_row_number})", end="\r")
content = c.fetchone()
with
i += 1
print(content["_id"])
content = c.fetchone()
When you run that, the next row the printed _id
should be the row that causing the problem.
This is the HEX and ASCII: 0000 4b 65 65 70 20 69 74 20 75 70 f0 9f 92 90 f0 9f Keep it up...... 0010 92 90 f0 9f 92 90 f0 9f 8c b9 f0 9f 8c b9 f2 a3 ................ 0020 b0 bd f0 b7 a0 bd f0 b7 a0 bd ed b2 9e .............
This is the HEX and ASCII: 0000 4b 65 65 70 20 69 74 20 75 70 f0 9f 92 90 f0 9f Keep it up...... 0010 92 90 f0 9f 92 90 f0 9f 8c b9 f0 9f 8c b9 f2 a3 ................ 0020 b0 bd f0 b7 a0 bd f0 b7 a0 bd ed b2 9e .............
Also, can you figure out the actual message shown in WhatsApp? Btw, just a reminder, do not post it publicly if it is a sensitive message.
You see, I have lost the Whatsapp encryption key and was only able to get the key file and this was before I deleted all of the Whatsapp backups. Do you see anything sensitive in that message? I don't know HEX.
Hey, I am worried now, what is that HEX? 😰
Hey so I did this:
echo 4b656570206974207570f09f9290f09f9290f09f9290f09f8cb9f09f8cb9f2a3b0bdf0b7a0bdf0b7a0bdedb29e | xxd -r -p
And got this:
Keep it up💐💐💐🌹🌹
Is there a way to ignore this error and let It run?
Hey, I am worried now, what is that HEX? cold_sweat
I don't mean to scare you. I have yet to look into the hex before you post the result tbh.
Is there a way to ignore this error and let It run?
The easiest way is use a try except block and skip it but it is not an ideal solution.
I am still trying to reproduce it because the exporter failed after inserting a row with your binary content, but I got a different error than yours.
Traceback (most recent call last):
...
File "...\Whatsapp_Chat_Exporter\extract.py", line 371, in messages
if "\r\n" in msg:
TypeError: a bytes-like object is required, not 'str'
Does my screenshot below have any difference from yours?
Yes there is! The first row is missing a 9f at the end. And the 2nd row is missing an a3 at the end.
Oh. They are just being hidden😂. Here you are:
Hah, there is no difference than. Did you try changing It from binary mode to text or RTL text?
Hah, there is no difference than. Did you try changing It from binary mode to text or RTL text?
They can't be displayed in text or RTL mode. Try this and post the output:
SELECT quote(text_data) from message WHERE _id=<the message id>;
If you are using Linux/WSL:
$ sqlite3 msgstore.db
> SELECT quote(text_data) from message WHERE _id=<the message id>;
'Keep it up💐💐💐🌹🌹���' Thanks. I got this.
'Keep it upbouquetbouquetbouquetroserose���' Thanks. I got this.
Hmmm, you are supposed to get a hex string. Something like this:
I didn't get a hex. What version of sqlite3 command line are you using? I am on 3.34.1.
Why is there no id in your command?
I didn't get a hex. What version of sqlite3 command line are you using? I am on 3.34.1.
3.40.1
Why is there no id in your command?
Look closer and you will find that it is just redacted😂. It should be an integer anyway.
Oh. Why would you redact that?! I have just tried It with version 3.42.0 and It's still not giving me the hex.
Oh. Why would you redact that?! I have just tried It with version 3.42.0 and It's still not giving me the hex.
I guess that's mean we have different data in that cell.
Why are getting a hex anyway, the cell should contain the message, not the hex, right?
Can you put the raw data into the cell?
Why are getting a hex anyway, the cell should contain the message, not the hex, right?
Yeah, I am trying to understand what raw data you got and how I can put the raw data into the cell. Hex is just one of the possible solutions, but we proved that we have different data inside the cell already by using hex. quote() function does not necessarily output hex but also just a quoted text.
What about this:
sqlite3 -line msgstore.db 'SELECT quote(text_data) from message WHERE _id=<id>;' | hexdump -C
But quote(text_data) = is also going to be here so the hex won't match. Would It?
And can you please write that python except block for now?
It will also have the quotes in the hex right? Wouldn't that be modifying the hex?
Implemented the workaround for the problem in 9ac8839.
It will also have the quotes in the hex right? Wouldn't that be modifying the hex?
It doesn't necessarily be hex.
Does the workaround skip It or does It try to extract It?
Implemented the workaround for the problem in 9ac8839.
It will also have the quotes in the hex right? Wouldn't that be modifying the hex?
It doesn't necessarily be hex.
Did you put in the hex in the cell or the text?
Does the workaround skip It or does It try to extract It?
The workaround skip the message.
Did you put in the hex in the cell or the text?
I put the hex in the hex area of the cell.
Could It be that It didn't get translated? Why don't you translate It externally and put It in as text?
Does the workaround skip It or does It try to extract It?
The workaround skip the message.
Did you put in the hex in the cell or the text?
I put the hex in the hex area of the cell.
This is the output: 00000000 71 75 6f 74 65 28 74 65 78 74 5f 64 61 74 61 29 |quote(text_data)| 00000010 20 3d 20 27 4b 65 65 70 20 69 74 20 75 70 f0 9f | = 'Keep it up..| 00000020 92 90 f0 9f 92 90 f0 9f 92 90 f0 9f 8c b9 f0 9f |................| 00000030 8c b9 f2 a3 b0 bd f0 b7 a0 bd f0 b7 a0 bd ed b2 |................| 00000040 9e 27 0a |.'.| 00000043
This is the plain hex, 71756f746528746578745f6461746129203d20274b656570206974207570f09f9290f09f9290f09f9290f09f8cb9f09f8cb9f2a3b0bdf0b7a0bdf0b7a0bdedb29e270a
If you don't mind you can send me your database. It will the the easiest way to do debugging.
No can do.
You can say Hi to me in the Matrix room and send the database to me through Matrix or send me an email with the link to the database at hello [at] knugi.com. You can find my PGP key at https://keyserver1.pgp.com.
Isn't there a way to extract a specific row from the database?
Can you send me an INSERT statement to that row?
Pardon my ignorance but how do I do that?
Use a supported browser to do it. Select the whole row and copy it as SQL.
Mailed you.
Hello, I suspect that this is due to some of the database not being in UTF-8. I got around this on another program that also exports Whatsapp messages by adding the following code:
db.text_factory = lambda b: b.decode(errors = 'ignore')
after this code which was already there,db = sqlite3.connect(file_path)
But when I tried to do this in this program, I couldn't find It in the extract python files. I instead found, this....Which is beyond my understanding.