Closed minanagehsalalma closed 4 years ago
Two step to get your wordlist:
python pydictor.py -base dL --len 8 8 -o init.dic
python pydictor.py -tool handler init.dic --occur "==6" "==2" "==0" -o final.dic
but there is huge items in init.dic
,there will be generate 36^8 = 2.8211099e+12
lines,It will take a very long time.
Hmm... thanks mate... can you explain the commands a little bit.
"-base dL" "-tool handler"
but there is huge items in
init.dic
,
But i don't have that kind of space.
Is there a way to generate the final.dic directly?
Also can the letters occur be two numbers Not just one So this "--occur "==6""
Be like this "--occur "==6/7" and "==1/2"
No way to directly generate the final.dic so far, except to modifying the code.
except to modifying the code.
Hmm which part ;)
I think it can some how be generated using hash cat masks.
Something like this ?l?d?l?l?l?d?l?l
But i do need to redo it many times to ensure the two numbers are every where in the wordlist ... i don't even know if it can be used to output into a wordlist.
Or maybe using policygen but i don't know how to convert a mask to a wordlist.
just like this 1d5ghlbz