B0501 判斷是否為迴文

[Leeee1111]

def is_palindrome(s):
    s = ''.join(c.lower() for c in s if c.isalnum())
    return s == s[::-1]

input_string = input()

if is_palindrome(input_string):
    print("YES")
else:
    print("NO")

[Leeee1111]

a=str(input())
if a[:len(a)//2] == a[:(len(a)-1)//2:-1]:
    print("YES")
else:
    print("NO")