comment for make_curl_post_files(data): says
"""Convert parameters dict, list or tuple to cURL style tuple"""
but list actually call's an error:
raise ValueError("%s argument must be list, tuple or dict, not %s" %
("make_curl_post_files", type(data)))
class Request(object):
def __init___(self, ...):
...
# String, dict, tuple, list
if isinstance(data, (StringTypes, NoneType)):
self._data = data
else:
self._data = data_wrapper(data)
def data_wrapper(data):
"""Convert data to list and returns
"""
...
def build_opener(self, url, opener=None):
...
if self._files is not None:
post_params = self._files
if isinstance(self._data, (TupleType, DictType)):
post_params.extend(data_wrapper(self._data))
opener.setopt(opener.HTTPPOST, post_params)
so we will never get to post_params.extend(data_wrapper(self._data)) if we are trying to send some files, because data is going to be wrapped in list in Request constructor.
comment for make_curl_post_files(data): says """Convert parameters dict, list or tuple to cURL style tuple""" but list actually call's an error: raise ValueError("%s argument must be list, tuple or dict, not %s" % ("make_curl_post_files", type(data)))
Also in agreed with this pull request https://github.com/Lispython/human_curl/pull/14:
due to this code
so we will never get to post_params.extend(data_wrapper(self._data)) if we are trying to send some files, because data is going to be wrapped in list in Request constructor.