Closed ericpre closed 1 year ago
From https://github.com/hyperspy/hyperspy-extensions-list/actions/runs/3119041322/jobs/5058746331
=================================== FAILURES =================================== ______________________ TestLumiSpectrum.test_errors_raise ______________________ a = [array([ 0. , 5.44444444, 10.88888889, 16.33333333, 21.77777778, [27](https://github.com/hyperspy/hyperspy-extensions-list/actions/runs/3119041322/jobs/5058746331#step:16:28).22222222, [32](https://github.com/hyperspy/hyperspy-extensions-list/actions/runs/3119041322/jobs/5058746331#step:16:33).66666667, 38.11111111,...., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1.])] @array_function_dispatch(_shape_dispatcher) def shape(a): """ Return the shape of an array. Parameters ---------- a : array_like Input array. Returns ------- shape : tuple of ints The elements of the shape tuple give the lengths of the corresponding array dimensions. See Also -------- len : ``len(a)`` is equivalent to ``np.shape(a)[0]`` for N-D arrays with ``N>=1``. ndarray.shape : Equivalent array method. Examples -------- >>> np.shape(np.eye(3)) (3, 3) >>> np.shape([[1, 3]]) (1, 2) >>> np.shape([0]) (1,) >>> np.shape(0) () >>> a = np.array([(1, 2), (3, 4), (5, 6)], ... dtype=[('x', 'i4'), ('y', 'i4')]) >>> np.shape(a) (3,) >>> a.shape (3,) """ try: > result = a.shape E AttributeError: 'list' object has no attribute 'shape' /usr/share/miniconda3/lib/python3.10/site-packages/numpy/core/fromnumeric.py:20[33](https://github.com/hyperspy/hyperspy-extensions-list/actions/runs/3119041322/jobs/5058746331#step:16:34): AttributeError During handling of the above exception, another exception occurred: self = <lumispy.tests.signals.test_luminescence_spectrum.TestLumiSpectrum object at 0x7f5d5c5a2500> def test_errors_raise(self): s = LumiSpectrum(np.ones(50)) for bkg, error in error_backgrounds: with pytest.raises(error): > s.remove_background_from_file(bkg) /usr/share/miniconda3/lib/python3.10/site-packages/lumispy/tests/signals/test_luminescence_spectrum.py:60: _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ /usr/share/miniconda3/lib/python3.10/site-packages/lumispy/signals/luminescence_spectrum.py:553: in remove_background_from_file if np.shape(background_xy)[0] == 1: <__array_function__ internals>:200: in shape ??? _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ a = [array([ 0. , 5.44444444, 10.88888889, 16.33333333, 21.77777778, 27.22222222, 32.66666667, 38.11111111,...., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1., 1.])] @array_function_dispatch(_shape_dispatcher) def shape(a): """ Return the shape of an array. Parameters ---------- a : array_like Input array. Returns ------- shape : tuple of ints The elements of the shape tuple give the lengths of the corresponding array dimensions. See Also -------- len : ``len(a)`` is equivalent to ``np.shape(a)[0]`` for N-D arrays with ``N>=1``. ndarray.shape : Equivalent array method. Examples -------- >>> np.shape(np.eye(3)) (3, 3) >>> np.shape([[1, 3]]) (1, 2) >>> np.shape([0]) (1,) >>> np.shape(0) () >>> a = np.array([(1, 2), (3, 4), (5, 6)], ... dtype=[('x', 'i4'), ('y', 'i4')]) >>> np.shape(a) (3,) >>> a.shape (3,) """ try: result = a.shape except AttributeError: > result = asarray(a).shape E ValueError: setting an array element with a sequence. The requested array has an inhomogeneous shape after 1 dimensions. The detected shape was (2,) + inhomogeneous part. /usr/share/miniconda3/lib/python3.10/site-packages/numpy/core/fromnumeric.py:20[35](https://github.com/hyperspy/hyperspy-extensions-list/actions/runs/3119041322/jobs/5058746331#step:16:36): ValueError
From https://github.com/hyperspy/hyperspy-extensions-list/actions/runs/3119041322/jobs/5058746331