Open Luzhiled opened 2 years ago
提出: https://onlinejudge.u-aizu.ac.jp/services/review.html#ACPC_2022_05_23/6666817
#include <bits/stdc++.h> using namespace std; // template {{{ using i32 = int; using u32 = unsigned int; using i64 = long long; using u64 = unsigned long long; #define range(i, l, r) for (i64 i = (i64)(l); i < (i64)(r); (i) += 1) #define rrange(i, l, r) for (i64 i = (i64)(r) - 1; i >= (i64)(l); (i) -= 1) #define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x) #define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x) #define debug(x) cerr << "(" << __LINE__ << ")" << #x << ": " << (x) << endl constexpr i32 inf = 1001001001; constexpr i64 infll = 1001001001001001001ll; constexpr i32 dx[] = {0, -1, 1, 0, -1, 1, -1, 1}; constexpr i32 dy[] = {-1, 0, 0, 1, -1, -1, 1, 1}; struct IoSetup { IoSetup(i32 x = 15){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup; template <typename T = i64> T input() { T x; cin >> x; return x; } template <typename T> ostream &operator<<(ostream &os, vector<T> &v) { range(i, 0, v.size()) { os << v[i] << (i + 1 != (int)v.size() ? " " : ""); } return os; } template <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; } template <typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p) { os << "(" << p.first << ", " << p.second << ")"; return os; } template <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; } template <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); } template <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); } template <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); } template <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); } // }}} #include "src/base.hpp" #include "src/product.hpp" using namespace geometry; real_number calc(const vector< real_number > &rs) { // n := rs.size(), 3 \leq n // maximize \sum{ rs[i] * rs[(i + 1) % n] * sin(ts[i]) } // s.t. \sum{ ts[i] } - 2PI = 0 // // f(ts[0], ts[1], ..., ts[n-1]) = \sum{ rs[i] * rs[(i+1)%n] * sin(ts[i]) } // g(ts[0], ts[1], ..., ts[n-1]) = \sum{ ts[i] } - 2PI // // Lagrange function L := // L(ts[0], ts[1], ..., ts[n-1]) = f - \lambda g // = \sum{ rs[i] * rs[(i+1)%n] * sin(ts[i]) } - \lamdba (\sum{ ts[i] } - 2PI ) // // rs[0] * rs[1] * cos(ts[0]) - \lamdba // = ... // = rs[i] * rs[(i+1)%n] * cos(ts[i]) - \lamdba // = ... // = 0 // // \lamdba = rs[0] * rs[1] * cos(ts[0]) // => rs[i] * rs[(i+1)%n] * cos(ts[i]) - rs[0] * rs[1] * cos(ts[0]) = 0 // => rs[i] * rs[(i+1)%n] * cos(ts[i]) = rs[0] * rs[1] * cos(ts[0]) // => cos(ts[i]) = (rs[0] * rs[1])/(rs[i] * rs[(i+1)%n]) * cos(ts[0]) // // as[i] := (rs[0] * rs[1]) / (rs[i] * rs[(i+1)%n]) // ts[0] = m, ts[i] = acos(as[i] * cos(ts[0])), and \sum{ ts[i] } = 2PI // => binary search assert(rs.size() >= 3); int n = rs.size(); auto make_ts = [&](real_number t0) { vector< real_number > ts; range(i, 0, n) { real_number a = (rs[0] * rs[1]) / (rs[i] * rs[(i+1)%n]); ts.emplace_back(acosl(clamp(a * cos(t0), real_number(-1), real_number(1)))); } return ts; }; real_number lb = 0, ub = PI; range(qi, 0, 200) { real_number m = (lb + ub) / 2; vector< real_number > ts = make_ts(m); real_number theta_sum = whole(accumulate, ts, real_number(0)); if (theta_sum < 2 * PI) lb = m; else ub = m; } real_number S = 0; vector< real_number > ts = make_ts(lb); if (not equals(whole(accumulate, ts, real_number(0)), 2 * PI)) return S; range(i, 0, n) { S += rs[i] * rs[(i+1)%n] * sinl(ts[i]); } return S / 2; } void solve() { int n = input(); vector< real_number > rs(n); cin >> rs; whole(sort, rs); real_number ans = 0; range(bit, 0, 1 << n) { vector< real_number > subset_r; range(i, 0, n) { if (~bit & (1 << i)) continue; subset_r.emplace_back(rs[i]); } if (subset_r.size() < 3) continue; do { chmax(ans, calc(subset_r)); } while (next_permutation(subset_r.begin() + 1, subset_r.end())); } cout << ans << endl; } signed main() { solve(); }
提出: https://onlinejudge.u-aizu.ac.jp/services/review.html#ACPC_2022_05_23/6666817