Closed lewtds closed 3 years ago
Which branch and commit are you using? I tried with the up-to-date master branch and got the correct result. See https://dtai.cs.kuleuven.be/problog/editor.html#task=lfi&hash=0c5c2f50ff039c30017da8796a95e906&ehash=0c26480cab02e6bf4608c5fa7621074f
On 16 Dec 2020, at 09:16, Trung Ngo notifications@github.com<mailto:notifications@github.com> wrote:
Hi. Aren't elements in an annotated disjunctions supposed to be mutually exclusive? Apparently, when learning the params, I still have to provide the negative evidences for the other alternatives. Otherwise, the propabilities come up being equal.
Example:
% model.pl t()::f(a); t()::f(b); t(_)::f(c).
With lfi --normalize, the result is [0.33333333, 0.33333333, 0.33333333]. I expect [0.4, 0.4, 0.2].
If I change it to this then it works correctly:
% model.pl t()::f(a); t()::f(b); t(_)::f(c).
pairwise_true :- f(a), f(b). pairwise_true :- f(b), f(c). pairwise_true :- f(c), f(a).
Thanks!
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I'm using the lastest develop branch. This commit https://github.com/ML-KULeuven/problog/commit/bc5d9f7be49e9a001b8b59989e8997821756b090
I'm not on my laptop now. I'll double check with master and post the exact command + env later.
Ohh that’s the issue. The develop branch is not up-to-date with the LFI feature. The stable LFI is in the master branch, the develop LFI is the feature/lficont branch.
On 16 Dec 2020, at 11:29, Trung Ngo notifications@github.com<mailto:notifications@github.com> wrote:
I'm not on my laptop now. I'll double check with master and post the exact command + env later.
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Thanks again! I can confirm that it works on master. But on lficont, it gives me 0.4::f(a); 0.4::f(a); 0.4::f(b); 0.4::f(b); 0.2::f(c)
. Maybe you can take a look on that.
Yes. The newest commit on LFI is wrong (work in progress), please rollback to fff2178ce7a5f983dbc7a0618120bfe9ad5f2b21
On 16 Dec 2020, at 20:52, Trung Ngo notifications@github.com<mailto:notifications@github.com> wrote:
Thanks again! I can confirm that it works on master. But on lficont, it gives me 0.4::f(a); 0.4::f(a); 0.4::f(b); 0.4::f(b); 0.2::f(c). Maybe you can take a look on that.
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Hi. Aren't elements in an annotated disjunctions supposed to be mutually exclusive? Apparently, when learning the params, I still have to provide the negative evidences for the other alternatives. Otherwise, the propabilities come up being equal.
Example:
With
lfi --normalize
, the result is[0.33333333, 0.33333333, 0.33333333]
. I expect[0.4, 0.4, 0.2]
.If I change it to this then it works correctly:
Thanks!