Closed GoogleCodeExporter closed 9 years ago
This is because the class above is declared "package-private". "package-private"
means neither "private", nor "public", nor "protected" modifier is used.
ModifierSet
can only check if a modifier was actually used in the parsed code.
Original comment by michaelkoch6@googlemail.com
on 15 Jan 2010 at 10:06
Thanks michaelkoch6.
It seems rodrigo had a little mistake. Am I right?
I will close this issue until this mistake be demystified.
Original comment by jges...@gmail.com
on 15 Jan 2010 at 3:14
Hi,
i think it should be useful to have that "package private" modifier in the
parser.
i'm making a diff. tool and out of the box i can't know if the modifier has
changed
from package private to just private (or other).
To solve the issue i had to implement a exhaustive if (if it's not private, not
public, etc. then it should be package private). It's not a very clean
solution, it
would be nicer if the parser could answer "ModifierSet.isPackagePrivate(...)".
Just my opinion ;)
Original comment by rodrigo....@gmail.com
on 15 Jan 2010 at 3:22
package private means the lack of modifiers. This is why there is no flag for
this.
If the method "ModifierSet.isPackagePrivate(...)" existed, it's implementation
should
be composed by the same ifs you've done in your code.
I agree with you that in some situations it could be useful. But it shouldn't be
implemented in the class "ModifierSet". Maybe in a helper class.
Original comment by jges...@gmail.com
on 15 Jan 2010 at 3:31
Well, maybe a method "hasModifiers()" or something like that make more sence, i
see
the point for not having a package private modifier (as modifiers do that,
explicitly change the default package private behavior).
Original comment by rodrigo....@gmail.com
on 15 Jan 2010 at 3:43
Original issue reported on code.google.com by
rodrigo....@gmail.com
on 23 Nov 2009 at 3:58