Closed jgray-19 closed 1 year ago
Simplify rbend fringe to solve backtracking for rbend true parallel
not clear to me that it is changing anything but may do some useless calculation in one case over two...
The only difference is that e2 and e1 are swapped when sdir == -1 in the calculation of c.a
Simplify rbend fringe to solve backtracking for rbend true parallel