Open MichalLytek opened 6 years ago
more info about the need to provide explicit type
Type definition error text is unclear. For example, if I try to use output type in mutation, I got an error
(node:10303) UnhandledPromiseRejectionWarning: Error: Cannot determine GraphQL input type for filter
How to figure out what exactly type was missed?
It would be nice to provide some additional info:
Describe the bug
I have CRM.Client
and ClientImpl
with the second being annotated as
@tq.ObjectType({ implements: CRM.Client }) export abstract class ClientImpl extends CRM.Client {
when CRM.Client is not annotated with @InterfaceType
the error message has no data to help fix the issue.
The code throwing the error is at : node_modules/type-graphql/dist/schema/schema-generator.js:157:59)
possible solution something along the lines of:
let interfaces = interfaceClasses.map(interfaceClass =>{
let ifdef= this.interfaceTypesInfo.find(info => info.target === interfaceClass)
if(ifdef) {return ifdef.type}
else{ console.error("can't find interface definition for",interfaceClass," in ",objectType.target) }
immediately gives away the culprit.
Enviorment (please complete the following information):
This issue is really important.
This is an extremely important issue.
I have a fairly complex Graphql schema using typegraphql and wasn't getting any typescript errors. However, when buildschema was executed after some time it started throwing "Cannot determine Graphql output type for items" errors. But, I have no clue where the issue exactly is.
I already have the following set:
"esModuleInterop": true,
"allowSyntheticDefaultImports": true,
@Query
decorator wont work on static functions
@Query(() => User)
static user(@Arg('username') username: string): User {
return mockedUsers.find((user) => user.username === username);
}
produces this while executing request to ... user(username:"test"){ ...
TypeError: Cannot read property 'apply' of undefined in .../type-graphql/dist/resolvers/create.js:19:64
Would be great to get a more semantic error here.
I've added a bunch of changes to errors system in 0.18.0-beta.16
release:
@Args
with @InputType
or without @ArgsType
@InterfaceType
on class provided to { implements: SomeClass }
(@gdanov)GeneratingSchemaError
occuredPlease let me know if the new error messages are informative enough or they have missing some valuable info 😉
Loving the new error messages! I can only guess how much time this error message has saved me Error: The value used as a type of '@Args' for 'addProduct' of 'ProductResolver' is not a class decorated with '@ArgsType' decorator!
Error: Cannot set property
prop
of #<ObjectType
> which has only a getter this error could be more specific, and point out that InputTypes (or ObjectTypes with an InputType alias) cannot have aget
member, you have to split up the classes
I have a key in the collection which suppose to be an object but the schema is not fixed for it. What will be the type of that in Model for typeorm, @typegoose/typegoose?? Getting Error: Cannot determine GraphQL output type for 'attributes' of 'XModel' class. Does the value used as its TS type or explicit type is decorated with a proper decorator or is it a proper output value? the attribute is one of the key of collection XModel.
Sample Code:
@Field(() => Object || null, { nullable: false })
@prop({ unique: false, required: true })
@Column()
public attributes!: object | null;
@himharsh1997 Use graphql-type-json
library. Where do your ||
syntax come from (Object || null
)?
My issue got resolved from one of your feedback of GitLab issues where you mention using graphql-type-json. But why it give the same error if I set type as any?
@himharsh1997 Because what any
means in GraphQL? String scalar? Boolean? It has to be the special JSON scalar for any
data. And Typescript reflection system is limited, things like {}
or any
or Record<string, number>
are reflected as Object
in runtime, so TypeGraphQL throws an error.
Error: You need to provide explicit type for MessageResolver#subscription !
Much better description for this error is needed.
The subscription for which this error is being thrown:
@Subscription({
topics: "NEW_MESSAGE"
})
subscription(
@Root() messagePayload: Object
): any {
// const messages = await Message.query('SELECT * FROM MESSAGE')
// const channel = Math.random().toString(36).slice(2, 15);
// onMessagesUpdate(() => pubSub.publish(channel, { messages }));
// setTimeout(() => pubSub.publish(channel, { messages }), 0);
// return pubSub.asyncIterator(channel);
return messagePayload
}
As you can see I have provided an explicit type any. I also provided some more types like Object
and MessagePayload
(custom type). None of them worked. Would love some help.
@antriksh123 Looks like you're not using v1.0+ which has different error messages
@antriksh123 Looks like you're not using v1.0+ which has different error messages
Oh yeah, I'm using 0.17.5. Okay, so will this error be resolved in v1?
I've already posted solution to your issue in Gitter. It won't be automagically resolved, it's a user error.
Have you read the docs at all? It's all described there when and how to provide graphql types.
in the docs for subscription, there wan't any info on providing type in the @Subscription()
decorator.
Providing types is described in types and fields docs - please read the whole docs and use search instead of asking such questions: https://typegraphql.com/docs/types-and-fields.html
Can we implement this in V2?
@carlocorradini I think it's out of scope. V2 is a maintance release, we can't put there everything, we need to release it quickly. It will be implemented in V3 rewrite.
Please feel free to comment in this issue and tell what check is missing or what check throw not detailed errors!
@Args
with@InputType
or without@ArgsType
reflect-metadata
polyfill@InterfaceType
on class provided to{ implements: SomeClass }
(@gdanov)GeneratingSchemaError
occured@Args()
@Arg
with@ArgsType
classFunction.name
)undefined
or other invalid values provided by mistake intype => X
target
setting and arrow function detection issue (#206, #219)defaultValue
option in@Field
placed in@ObjectType
@FieldResolver
than in@Field()