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MikeInnes / DataFlow.jl

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The example doesn't run in Julia 0.6 #9

Open xiaodaigh opened 7 years ago

xiaodaigh commented 7 years ago

I tried the following code in Julia 0.6 and it gave me an error. So I tried to checkout release-0.2 and rerun and it still gives me an error.

using DataFlow
@flow function var(xs)
  mean = sum(xs)/length(xs)
  meansqr = sumabs2(xs)/length(xs)
  meansqr - mean^2
end

xs = DataFlow.cse(var.output)
DataFlow.IVertex{Any}
chamois = length(xs)
sumabs2(xs) / chamois - (sum(xs) / chamois) ^ 2