The code that checks if the name in a local name declaration statement is an out parameter, part of the resolution to Issue #53, inadvertently causes a null pointer exception when the local name declaration has "any" as its type (i.e., no type name).
seidewitz
commented
6 years ago
The code that checks if the name in a local name declaration statement is an out parameter, part of the resolution to Issue #53, inadvertently causes a null pointer exception when the local name declaration has "any" as its type (i.e., no type name).