Closed queliyong closed 3 years ago
Thank you for your feedback, but...
This seems to be a problem with RDChiral being unable to create proper template. The reaction itself is a "simple" transformation reaction, and only has one product and one reactant, even though the template has two of each. Presumably because the molecule is symmetric.
I have encountered this a few times, and I have just simply removed this example from the template library.
Alternatively, you can bring up the discussion with the developers of RDChiral.
Thank you for your feedback, but...
This seems to be a problem with RDChiral being unable to create proper template. The reaction itself is a "simple" transformation reaction, and only has one product and one reactant, even though the template has two of each. Presumably because the molecule is symmetric.
I have encountered this a few times, and I have just simply removed this example from the template library.
Alternatively, you can bring up the discussion with the developers of RDChiral.
Get it. Thank U for your patient reply.
Hi, I extracted this reaction's retro template by rdchiral, as follows: '[OH;D1;+0:2]-[c:1].[OH;D1;+0:4]-[c:3]>>[c:1]-[O;H0;D2;+0:2]-C-c1:c:c:c:c:c:1.[c:3]-[O;H0;D2;+0:4]-C-c1:c:c:c:c:c:1'
Obviously, the template has two products, It can not be used to train the reaction. Any idea to train this type of reaction? Thank U very much. The reaction smiles is 'CC(C)(C)C1=CC(C2=C(CCCC3)C3=CC4=C2CCCC4)=C(OCC5=CC=CC=C5)C(C6=CC(C(C)(C)C)=CC=C6OC[C@@h]7CCCC[C@@h]7COC8=CC=C(C(C)(C)C)C=C8C9=CC(C(C)(C)C)=CC(C%10=C(CCCC%11)C%11=CC%12=C%10CCCC%12)=C9OCC%13=CC=CC=C%13)=C1>>OC1=C(C2=C(CCCC3)C3=CC4=C2CCCC4)C=C(C(C)(C)C)C=C1C5=CC(C(C)(C)C)=CC=C5OC[C@@h]6CCCC[C@@h]6COC7=CC=C(C(C)(C)C)C=C7C8=CC(C(C)(C)C)=CC(C9=C(CCCC%10)C%10=CC%11=C9CCCC%11)=C8O'