Closed rawrex closed 2 years ago
Since the T is deduced to be plain T (i.e. plain, non-reference int), the val will be of type int&&. There's no int&& &&, since T is a plain type.
Since the T is deduced to be plain T (i.e. plain, non-reference int), the val will be of type int&&. There's no int&& &&, since T is a plain type.