Open anu-shka-k opened 10 months ago
Please assign me with this issue Payal Chandak UEC2022118 Sy E&tc
Assigned, please create a PR within 2 days
Please create PR request not a reply
On Sat, 28 Oct, 2023, 4:20 PM Payalchandak5, @.***> wrote:
include
include
struct Node { int data; struct Node* next; };
struct Node mergeTwoLists(struct Node list1, struct Node list2) { struct Node dummy; struct Node tail = &dummy; dummy.next = NULL;
while (1) { if (list1 == NULL) { tail->next = list2; break; } else if (list2 == NULL) { tail->next = list1; break; }
if (list1->data <= list2->data) { tail->next = list1; list1 = list1->next; } else { tail->next = list2; list2 = list2->next; } tail = tail->next;
}
return dummy.next;
} struct Node mergeKSortedLists(struct Node lists[], int k) { if (k == 0) return NULL;
int last = k - 1; while (last != 0) { int i = 0, j = last; while (i < j) { lists[i] = mergeTwoLists(lists[i], lists[j]); i++, j--;
if (i >= j) last = j; }
}
return lists[0];
}
void printList(struct Node* node) { while (node != NULL) { printf("%d", node->data); if (node->next != NULL) printf("->"); node = node->next; } printf("->NULL\n"); }
int main() { int k, n; printf("Enter the number of linked lists (K): "); scanf("%d", &k); printf("Enter the size of each list (N): "); scanf("%d", &n);
struct Node* lists[k];
for (int i = 0; i < k; i++) { printf("list %d: ", i + 1); lists[i] = NULL; struct Node* current = NULL;
for (int j = 0; j < n; j++) { int value; scanf("%d", &value); struct Node* newNode = (struct Node*)malloc(sizeof(struct Node)); newNode->data = value; newNode->next = NULL; if (lists[i] == NULL) { lists[i] = newNode; current = newNode; } else { current->next = newNode; current = newNode; } }
}
struct Node* result = mergeKSortedLists(lists, k); printf("Merged Sorted List: "); printList(result);
return 0;
}
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Yes did
tag this issue so it can be merged otherwise it cant be merged
On Sun, Oct 29, 2023 at 6:14 PM Payalchandak5 @.***> wrote:
Yes did
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Given K sorted linked lists of size N each, the task is to merge them all maintaining their sorted order.
Input: K = 3, N = 4 list1 = 1->3->5->7->NULL list2 = 2->4->6->8->NULL list3 = 0->9->10->11->NULL Output: 0->1->2->3->4->5->6->7->8->9->10->11
Input: K = 3, N = 3 list1 = 1->3->7->NULL list2 = 2->4->8->NULL list3 = 9->10->11->NULL Output: 1->2->3->4->7->8->9->10->11