Open toomanynights opened 6 months ago
This function is mentioned here, but it throws an error. I didn't find it in the code. There is a workaround however: one can simply request UI.isUIVisible.
UI.isUIVisible
This function is mentioned here, but it throws an error. I didn't find it in the code. There is a workaround however: one can simply request
UI.isUIVisible
.